Se N>1, o valor da expressão...

por **Bryan Sales** » Dom Jul 20, 2014 00:20

$\sqrt[3]{N\sqrt[3]{N\sqrt[3]{N}}} = A){N}^{\frac{1}{27}} B){N}^{\frac{1}{9}} C){N}^{\frac{1}{3}} D){N}^{\frac{13}{27}} E)N$

Obrigado

por **DanielFerreira** » Dom Jul 20, 2014 11:45

Olá Bryan,
seja bem-vindo!

$\\ \sqrt[3]{N\sqrt[3]{N\sqrt[3]{N}}} = \\\\ \sqrt[3]{N\sqrt[3]{\sqrt[3]{N^3 \cdot N}}} = \\\\ \sqrt[3]{N\sqrt[9]{{N^4}}} = \\\\ \sqrt[3]{\sqrt[9]{{N^9 \cdot N^4}}} = \\\\ \sqrt[27]{{{N^{13}}}} = \\\\ \boxed{N^{\frac{13}{27}}}$