Dados os conjuntos A={1,3,4},B={-2,1},c={-1,0,2} represente pelos elementos
a) AXB
B)BXA
C)AXC
RESPOSTAS:
a) AXB = {(1,-2), (3,-2), (4,-2), (1,1), (3,1), (4,1)}
b) BXA = {(-2,1), (1,1), (-2,3), (1,3), (-2,4), (1,4)}
c) AXC = {(1,-1), (3,-1), (4,-1), (1,0), (3,0), (4,0), (1,2), (3,2), (4,2)}
![{(0,05)}^{-\frac{1}{2}}=\frac{10}{\sqrt[5]}](/latexrender/pictures/19807748a214d3361336324f3e43ea9a.png "{(0,05)}^{-\frac{1}{2}}=\frac{10}{\sqrt[5]}")
![{(0,05)}^{-\frac{1}{2}}=\frac{10}{\sqrt[2]{5}}](/latexrender/pictures/3d7908e5b4e397bf635b6546063d9130.png "{(0,05)}^{-\frac{1}{2}}=\frac{10}{\sqrt[2]{5}}")
, ou seja, 1 dividido por 20 é igual a 0.05 . Sendo assim, a função final é igual a vinte elevado à meio. ![{0,05}^{-\frac{1}{2}} = {\frac{1}{20}}^{-\frac{1}{2}} = {\frac{20}{1}}^{\frac{1}{2}} = \sqrt[2]{20}](/latexrender/pictures/c0100c6f4d8bdbb7d54165e6be7aff04.png "{0,05}^{-\frac{1}{2}} = {\frac{1}{20}}^{-\frac{1}{2}} = {\frac{20}{1}}^{\frac{1}{2}} = \sqrt[2]{20}")
da seguinte forma:
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da seguinte forma:
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