exercicio resolvido

por **adauto martins** » Sex Abr 23, 2021 15:59

(ITA-1954)mostrar que

${log}_{a}k/{log}_{a.m}k=1+{log}_{a}m$

por **adauto martins** » Sex Abr 23, 2021 16:09

soluçao

aqui usarei duas propriedades de mudança de base de logaritmos,a saber

${log}_{a}b=1/{log}_{b}a...{log}_{a}b={log}_{k}b/{log}_{k}a$

logo

${log}_{a}k/{log}_{m.a}k={log}_{k}(a.m)/{log}_{k}a= ({log}_{k}a + {log}_{k}m)/{log}_{k}a=1+({log}_{k}m/{log}_{k}a) =1+{log}_{a}m...$

exercicio resolvido

exercicio resolvido

exercicio resolvido

Re: exercicio resolvido

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