por Andrewo » Qui Abr 19, 2012 14:05
![\sqrt[12]{{2}^{3}.{a}^{6}}](/latexrender/pictures/2132be55b04d27134c15735f3bd39d1f.png "\sqrt[12]{{2}^{3}.{a}^{6}}")
e 
![\sqrt[4]{2}](/latexrender/pictures/2f92f26b5ec4b063312e1be4bafd7452.png "\sqrt[4]{2}")
e ![\sqrt[]{a}](/latexrender/pictures/3d48e387f88a173a4e4cf3b38dbab4a6.png "\sqrt[]{a}")
![\sqrt[4]{2.{a}^{2}}](/latexrender/pictures/ce73b25dcff3d2c7167d63e5e79adcf9.png "\sqrt[4]{2.{a}^{2}}")
????![{(1-\sqrt[]{2})}^{2}](/latexrender/pictures/064ba63db0deade10f842f254c26b8dc.png "{(1-\sqrt[]{2})}^{2}")
![(3-\sqrt[]{2})](/latexrender/pictures/65e7f9b3a3917d9ea8cd8e3083e426fa.png "(3-\sqrt[]{2})")
![(3-\sqrt[]{2})(3-\sqrt[]{2})](/latexrender/pictures/58f7576051e80abb42df2fce604d58aa.png "(3-\sqrt[]{2})(3-\sqrt[]{2})")
=![9-12\sqrt[]{2} + 8 = 17-12\sqrt[]{2}](/latexrender/pictures/280d932b46b0639153364cdd24ff81b8.png "9-12\sqrt[]{2} + 8 = 17-12\sqrt[]{2}")
![\frac{a-b}{\sqrt[]{a}-\sqrt[]{b}}](/latexrender/pictures/adcfd5a77f7da6b1e6ac10b12505fc59.png "\frac{a-b}{\sqrt[]{a}-\sqrt[]{b}}")
b ![\frac{a-b}{\sqrt[]{a}-\sqrt[]{b}}.\frac{\sqrt[]{a}+\sqrt[]{b}}{\sqrt[]{a}+\sqrt[]{b}}](/latexrender/pictures/4a80b60f385b88a718fa9bbdfb1e334e.png "\frac{a-b}{\sqrt[]{a}-\sqrt[]{b}}.\frac{\sqrt[]{a}+\sqrt[]{b}}{\sqrt[]{a}+\sqrt[]{b}}")
![\frac{a\sqrt[]{a}+a\sqrt[]{b}-b\sqrt[]{a}-b\sqrt[]{b}}{a-b}](/latexrender/pictures/d44e9bbebb6c4a01f2288595c3a64731.png "\frac{a\sqrt[]{a}+a\sqrt[]{b}-b\sqrt[]{a}-b\sqrt[]{b}}{a-b}")
«![\sqrt[]{a}+\sqrt[]{b}](/latexrender/pictures/17957293567ab489803a1248360d8334.png "\sqrt[]{a}+\sqrt[]{b}")
por DanielFerreira » Sáb Abr 21, 2012 13:46
Andrewo escreveu:Aí pessoal , blza? Algumas dúvidazinhas aí sobre radicais
Nessa pra simplificar, meu resultado não bateu
Simplificando fica:
=
Aí então não ficariam em raízes separadas já que o indicador mudou? =
Pq o resultado fica
![\sqrt[12]{2^3.a^6} =](/latexrender/pictures/61c755686471832d3ae75f87ff57e5bb.png "\sqrt[12]{2^3.a^6} =")
![\sqrt[4]{2} . \sqrt[]{a} =](/latexrender/pictures/60049d51c311b108664f5f6a26ca8674.png "\sqrt[4]{2} . \sqrt[]{a} =")
![\sqrt[n]{x}](/latexrender/pictures/13fcbed8bcac58d95c0cb989f3aca2de.png "\sqrt[n]{x}")
![\sqrt[4]{2} . \sqrt[4]{a^2} =](/latexrender/pictures/fb4f6f82d647fbd97a0dcf9cff77a778.png "\sqrt[4]{2} . \sqrt[4]{a^2} =")
![\sqrt[4]{2.a^2}](/latexrender/pictures/d81727c89e463f38666e8a3633fe55d0.png "\sqrt[4]{2.a^2}")
por DanielFerreira » Sáb Abr 21, 2012 13:55
Andrewo escreveu:Aí pessoal , blza? Algumas dúvidazinhas aí sobre radicais
2-
Como eu fiz :
Resultado pelo gabarito : 1
![(1 - \sqrt[]{2})^2(3 - \sqrt[]{2}) =](/latexrender/pictures/8077873616e12b369d8ea4e305d67eb8.png "(1 - \sqrt[]{2})^2(3 - \sqrt[]{2}) =")
![(1 - 2\sqrt[]{2} + 2)(3 - \sqrt[]{2}) =](/latexrender/pictures/c67779cec3dba68dbec8b388ecc68b8c.png "(1 - 2\sqrt[]{2} + 2)(3 - \sqrt[]{2}) =")
![(3 - 2\sqrt[]{2})(3 - \sqrt[]{2}) =](/latexrender/pictures/ffa52ccb838ed4a12b592d69214cce51.png "(3 - 2\sqrt[]{2})(3 - \sqrt[]{2}) =")
![(3 - 2\sqrt[]{2}) \neq(3 - \sqrt[]{2})](/latexrender/pictures/25aad3d31e331c1175a7084b93886e4c.png "(3 - 2\sqrt[]{2}) \neq(3 - \sqrt[]{2})")
![9 - 3\sqrt[]{2} - 6\sqrt[]{2} + 4 =](/latexrender/pictures/0de36282adb00ba1ef22579cfa05267c.png "9 - 3\sqrt[]{2} - 6\sqrt[]{2} + 4 =")
![13 - 9\sqrt[]{2}](/latexrender/pictures/0a7db61fc6505df805c802fa52f8746d.png "13 - 9\sqrt[]{2}")
por DanielFerreira » Sáb Abr 21, 2012 14:01
Andrewo escreveu:Aí pessoal , blza? Algumas dúvidazinhas aí sobre radicais
3 -
Como eu fiz :
=
Resultado pelo gabarito :
![\frac{a - b}{\sqrt[]{a} - \sqrt[]{b}}](/latexrender/pictures/df556b3fae7f7f752c6a39ae4f95d915.png "\frac{a - b}{\sqrt[]{a} - \sqrt[]{b}}")
=![\left(\frac{a - b}{\sqrt[]{a} - \sqrt[]{b}} \right).\left(\frac{\sqrt[]{a} + \sqrt[]{b}}{\sqrt[]{a} + \sqrt[]{b}} \right)](/latexrender/pictures/230998b4496f5237a2199d145d7f3094.png "\left(\frac{a - b}{\sqrt[]{a} - \sqrt[]{b}} \right).\left(\frac{\sqrt[]{a} + \sqrt[]{b}}{\sqrt[]{a} + \sqrt[]{b}} \right)")
=![\frac{(a - b)(\sqrt[]{a} + \sqrt[]{b})}{a - b}](/latexrender/pictures/c6e6d25414ab901201fd118ffae3f626.png "\frac{(a - b)(\sqrt[]{a} + \sqrt[]{b})}{a - b}")
=![\frac{1(\sqrt[]{a} + \sqrt[]{b})}{1}](/latexrender/pictures/c04b370d3ac2ecaaf13762c6c55799c0.png "\frac{1(\sqrt[]{a} + \sqrt[]{b})}{1}")
=![\sqrt[]{a} + \sqrt[]{b}](/latexrender/pictures/2e9c7b25c2340c81571cc55454c06f8c.png "\sqrt[]{a} + \sqrt[]{b}")
por DanielFerreira » Ter Abr 24, 2012 20:14
Usuários navegando neste fórum: Nenhum usuário registrado e 1 visitante
![\frac{\sqrt[]{\sqrt[4]{8}+\sqrt[]{\sqrt[]{2}-1}}-\sqrt[]{\sqrt[4]{8}-\sqrt[]{\sqrt[]{2}-1}}}{\sqrt[]{\sqrt[4]{8}-\sqrt[]{\sqrt[]{2}+1}}}](/latexrender/pictures/981987c7bcdf9f8f498ca4605785636a.png "\frac{\sqrt[]{\sqrt[4]{8}+\sqrt[]{\sqrt[]{2}-1}}-\sqrt[]{\sqrt[4]{8}-\sqrt[]{\sqrt[]{2}-1}}}{\sqrt[]{\sqrt[4]{8}-\sqrt[]{\sqrt[]{2}+1}}}")
![\sqrt[]{2}](/latexrender/pictures/f21662d1cabab6e8b273a4b6f1cd663a.png "\sqrt[]{2}")
(dica : igualar a expressão a 
e elevar ao quadrado os dois lados)